4. A fraction whose 1/3 when 1 is subtracted from the numerator and it becomes 1/4 when 8 is added to the denominator. Find the fraction. About the author Ella
Let us assume thenumerator to be =x Let us assume thedenominator to be =y Hence the fractionbecomes=x/y Accordingtothe given condition (x−1)/y=1/3 ⇒y=3x−3 ———-(i) Accordingtothesecond givencondition, x/(y+8)=1/4 ⇒y+8=4x ⇒y=4x−8 ————(ii) Combining(i)and(ii) we get, 3x−3=4x−8 ⇒3x−4x=−8+3 −x=−5 ⇒x=5 from(i) y=15−3=12 So,the fraction is =5/12 Reply
Answer:
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Let us assume thenumerator to be =x
Let us assume thedenominator to be =y
Hence the fractionbecomes=x/y
Accordingtothe given condition
(x−1)/y=1/3
⇒y=3x−3 ———-(i)
Accordingtothesecond givencondition,
x/(y+8)=1/4
⇒y+8=4x
⇒y=4x−8 ————(ii)
Combining(i)and(ii) we get,
3x−3=4x−8
⇒3x−4x=−8+3
−x=−5
⇒x=5
from(i)
y=15−3=12
So,the fraction is =5/12