4. एक गाडी विशिष्ट अंतर एकाच ठराविक वेगाने कापते. जर गाडीचा वेग 6 कि. मी
/तास वाढला असता तर ती तिच्या निर्धारित वेळेच्या 4 ता

2 thoughts on “4. एक गाडी विशिष्ट अंतर एकाच ठराविक वेगाने कापते. जर गाडीचा वेग 6 कि. मी<br />/तास वाढला असता तर ती तिच्या निर्धारित वेळेच्या 4 ता”

1. Answer:

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2. Step-by-step explanation:

   A train travels a certain distance at the same speed. If the speed of the vehicle is 6 kph. I
   / Hr, she arrives 4 hours earlier than her scheduled time. If the speed of the train was reduced to 6 km / hr, then the train would be 6 hours faster than its scheduled time It will take more. So how many km did the train travel in total?

   • Consider time taken as t, speed as x and Distance as d.
   • Time = Distance / Speed
   • So Speed = Distance / Time
   • x = d/t ———-1
   • Now for the first case we have
   • d = (x + 6) (t – 4)
   • d = xt + 6t – 4x – 24
   • d = d – 4x + 6t – 24
   • 6t – 4x = 24 ————2
   • Now for the second case we have
   • d = (x – 6) (t + 6)
   • d = xt + 6x – 6t – 36
   • d = d + 6x – 6t – 36
   • 6x – 6t = 36 —————-3
   • Adding equation 2 and 3 we get
   • 6t – 4x = 24
   • -6t + 6x = 36
   • 2x = 60
   • x = 30
   • Now substituting the value of x in eqn 2 we get
   • 6t – 4(30) = 24
   • 6t – 120 = 24
   • 6t = 24 + 120
   • 6t = 144
   • t = 144 / 6
   • t = 24 hours
   • Now substituting the value of t and x in equation 1 we get
   • Distance d = x t
   • = 30 x 24
   • Or d = 720 kms
     
   • Therefore the train travelled a distance of 720 kms
     

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