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313(ABP +BC2 + AC?)=4(ADP + BE? + CF2)
4) None
The diameter of a circle is AB and the chord CD is equal to the radius. L

By Eden

313(ABP +BC2 + AC?)=4(ADP + BE? + CF2)
4) None
The diameter of a circle is AB and the chord CD is equal to the radius. Lines AC
and BD intersect each other at point P, then find the value of P.
P
a​

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Eden

following pairs of points
Find the distance between the
1) A (1,4) B (2,3)
2) x (a, b) Y(-a-b)
​

Figure out the rule from the given example and write it using letters.
12 (10 + 2) = (12 x 10) + (12 x 2)

1 thought on “313(ABP +BC2 + AC?)=4(ADP + BE? + CF2)<br />4) None<br />The diameter of a circle is AB and the chord CD is equal to the radius. L”

  1. Answer:

    10.42,AB is a diameter of the circle,CD is a chord equal to the radius of the circle.AC and BD when extended intersect at point at E. Prove that ∠AEB = 60 degree . In Fig. 10.42,AB is a diameter of the circle,CD is a chord equal to the radius of the circle.AC and BD when extended intersect at point at E.

    Step-by-step explanation:

    i hope it’s helpful to u. ❤

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