31. A shopkeeper sold two fans for * 1140 each. On one he gains 14%, while on the other heloses 5%. Calculate his gain or loss per cent in the whole transaction. About the author Brielle
Given : Selling Price = Rs. 1140 Gain on one fan = 14% Loss on second fan = 5% To find : gain or loss percent Solution : Cost Price of Fan one = [tex]\sf \dfrac{100}{100 + profit \%} \times S.P[/tex] = [tex]\sf \dfrac{100}{100 + 14} \times 1140[/tex] = [tex]\sf \dfrac{100}{114} \times 1140[/tex] = [tex]\sf \dfrac{114000}{114}[/tex] = 1000 Cost Price of Fan two = [tex]\sf \dfrac{100}{100 – loss \%} \times S.P[/tex] = [tex]\sf \dfrac{100}{100 -5} \times 1140[/tex] = [tex]\sf \dfrac{100}{95} \times 1140[/tex] = [tex]\sf \dfrac{114000}{95}[/tex] = 1200 Let’s find the Total Selling Price and Cost price, Total Selling Price = 1140 + 1140 = 2280 Total Cost Price = 1000 + 1200 = 2200 Since, S.P > C.P [Hence, it is Profit.] Profit = S.P – C.P = 2280 – 2200 = 80 Now, Profit% = [tex]\sf \dfrac{Profit}{C.P} \times 100[/tex] = [tex]\sf \dfrac{80}{2200} \times 100[/tex] = [tex]\sf \dfrac{8000}{2200}[/tex] = 3.6% Therefore, the Profit% of the fan is 3.6%. Reply
Given :
To find :
Solution :
Cost Price of Fan one = [tex]\sf \dfrac{100}{100 + profit \%} \times S.P[/tex]
= [tex]\sf \dfrac{100}{100 + 14} \times 1140[/tex]
= [tex]\sf \dfrac{100}{114} \times 1140[/tex]
= [tex]\sf \dfrac{114000}{114}[/tex]
= 1000
Cost Price of Fan two = [tex]\sf \dfrac{100}{100 – loss \%} \times S.P[/tex]
= [tex]\sf \dfrac{100}{100 -5} \times 1140[/tex]
= [tex]\sf \dfrac{100}{95} \times 1140[/tex]
= [tex]\sf \dfrac{114000}{95}[/tex]
= 1200
Let’s find the Total Selling Price and Cost price,
= 2280
= 2200
Since, S.P > C.P [Hence, it is Profit.]
Profit = S.P – C.P
= 2280 – 2200
= 80
Now,
Profit% = [tex]\sf \dfrac{Profit}{C.P} \times 100[/tex]
= [tex]\sf \dfrac{80}{2200} \times 100[/tex]
= [tex]\sf \dfrac{8000}{2200}[/tex]
= 3.6%
Therefore, the Profit% of the fan is 3.6%.