27. Find the zeroes of the polynomial x2-3 and verify the relationship between thezeroes and the coefficients of the polynomial. About the author Kennedy
Answer: Here’s the answer Step-by-step explanation: x^2-3 => (x-√3)(x+√3) => x = √3 ,-√3 let aplha = √3 and beta = -√3 alpha +beta = -b/a = 0/1 =0 aplha × beta = c/a = -3/1 = -3 Reply
Answer:
Here’s the answer
Step-by-step explanation:
x^2-3
=> (x-√3)(x+√3)
=> x = √3 ,-√3
let aplha = √3 and beta = -√3
alpha +beta = -b/a
= 0/1
=0
aplha × beta = c/a
= -3/1
= -3