2/x square-32x+1/21. factorise


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1. Answer:

   Step-by-step explanation:

   To find the roots of the quadratic equation equate it to 0

   Let f(x)=21 x^{2}-2 x+\frac{1}{21}=0f(x)=21x

   2

   −2x+

   21

   1

   =0

   On taking LCM, we get,

   441 x^{2}-42 x+1=0441x

   2

   −42x+1=0

   The above in equation is in (a-b)^{2} = 0(a−b)

   2

   =0 form

   Where, a = 21x; b = 1

   On using, the above formula, we get,

   (21 x-1)^{2}=0(21x−1)

   2

   =0

   On solving, we get,

   21 x-1=0; \ \ 21 x-1=021x−1=0; 21x−1=0

   \Rightarrow 21 x=1; \ \ 21 x=1⇒21x=1; 21x=1

   Thus, the value of x are,

   x=\frac{1}{21}, \frac{1}{21}x=

   21

   1

   ,

   21

   1

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