2. One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of
the triangle.
3

2. One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of
the triangle.
3. The perimeter of a square is numerically equal to its area. Find its area.​

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Rylee

2 thoughts on “2. One of the equal sides of an isosceles triangle is 13 cm and its perimeter is 50 cm. Find the area of<br />the triangle.<br />3”

  1. Answer:Given that one of the equal line is of 13 cm, so length of other side should also be 13 cm. ∴Length of third side is 24 cm. therefore, applying heron’s formula for the area of the triangle. Therefore, area of the triangle is 60 cm^2

    Step-by-step explanation:

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  2. Step-by-step explanation:

    2. let the sides of triangle be AB, BC, CA.

    As isosceles triangle is the triangle that have 2 equal sides and one equal side is AB= BC = 13cm

    we are given that

    perimeter = 50cm

    AB + BC + CA = 50cm

    13 +13 + CA = 50

    26 + CA = 50

    CA = 50 – 26

    CA = 24cm.

    3. As perimeter of square = 4 × side

    area = side × side

    = (side) square

    so it is basically numerically equal to the area

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