2) In APQR, Q=90°, PQ = 8 cm and QR = 15 cm, then find the length of PR​

2 thoughts on “2) In APQR, Q=90°, PQ = 8 cm and QR = 15 cm, then find the length of PR​”

1. Given

   In triangle PQR, PQ= 8 cm QR= 15 cm and Q= 90

   therefore it is right angle triangle.

   Pythagoras theorem

   [tex]p {}^{2} = h {}^{2} + b {}^{2} [/tex]

   where p is PR or hypotenuse, h is PQ or height and b is QR or base.

   [tex]p {}^{2} = 8 {}^{2} + 15 ^{2} \\ p { }^{2} = 64 + 225 \\ p {}^{2} = 289 \\ p = \sqrt{289 } \\ p = 17[/tex]

   p = PR

   PR = 17 cm

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2. Answer:

   as angle Q = 90°

   hence.

   (PR)^2 = (QR)^2 + (PQ)^2

   PR^2 = 15×15+8×8

   PR =

   [tex] \sqrt{225 + 64 } [/tex]

   PR =

   [tex] \sqrt{289} [/tex]

   PR = 17cm this would be your answer.

   hope it helps you

   please mark my answer as brainliest.

   Reply