2.Find the zeroes of the given polynomials.(1) p(x) = 3x(iii) p(x) = (x+2)(x+3)(ii) p(x) = x + 5x + 6(iv) p(x) = x – 16 About the author Genesis
Answer: 1.p(0)=3(0)=0 2.p(0)=(0+2)(0+3)=(2)(3)=6 3.p(0)=0+5(0)+6=0+0+6=6 4.p(0)=0-16=-16 Step-by-step explanation: please follow, hope it helps you Reply
Answer:
1.p(0)=3(0)=0
2.p(0)=(0+2)(0+3)=(2)(3)=6
3.p(0)=0+5(0)+6=0+0+6=6
4.p(0)=0-16=-16
Step-by-step explanation:
please follow, hope it helps you