2. By rationalising the denominator of.
[tex] \sqrt{2} by \: \sqrt{5 + \sqrt{3} } [/tex]
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1 thought on “2. By rationalising the denominator of. <br />[tex] \sqrt{2} by \: \sqrt{5 + \sqrt{3} } [/tex]<br /> /​”

1. Answer:

   √10-√6/16.

   Step-by-step explanation:

   √2 / √5 + √3

   = √2 / √5+√3 * √5-√3/√5-√3

   = √2(√5-√3)/ (√5)^2-(√3)^2

   = √10 – √6 / 25-9

   = √10-√6/16. answer

   I hope it is useful for you.

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