2. A coin is tossed and a die is rolled simultaneously. 0) Condition for eventA: To get a tail and an even number. b) Condition for event B : To get a head or a tall and an odd number. About the author Bella
A coin is tossed we get ➠ ( H , T ) A die is rolled we get ➠ ( 1 , 2 , 3 , 4 , 5 , 6 ) Answer for condition for event A [tex]➠P ( tail) = \frac{ favourable \: outcome }{ total \: outcome}[/tex] [tex]➠\: P ( tail) \: = \frac{1}{2} [/tex] [tex]➠P( even \: number ) = \frac{favourable outcome }{ total outcome} [/tex] [tex]➠P( even number ) = \frac{3}{6} [/tex] [tex]➠P( even number ) = \frac{1}{2} [/tex] Answer for condition event B [tex]➠P ( head \: or \: tail ) = \frac{favourable \: outcome }{ total \: outcome} [/tex] [tex]➠P ( head \: or \: tail) = \frac{2}{2} [/tex] [tex]➠P ( head \: or \: tail) = 1[/tex] [tex]➠P( odd\: number ) = \frac{favourable outcome }{ total outcome} [/tex] [tex]➠P( odd \: number ) = \frac{3}{6} [/tex] [tex]➠P( odd \: number ) = \frac{1}{2} [/tex] Know more :- [tex]➠P( E ) = \frac{favourable outcome }{ total outcome} [/tex] [tex]➠P( E ) + P ( not E ) = 1[/tex] Reply
A coin is tossed we get
➠ ( H , T )
A die is rolled we get
➠ ( 1 , 2 , 3 , 4 , 5 , 6 )
Answer for condition for event A
[tex]➠P ( tail) = \frac{
favourable \: outcome }{
total \: outcome}[/tex]
[tex]➠\: P ( tail) \: = \frac{1}{2} [/tex]
[tex]➠P( even \: number ) = \frac{favourable outcome }{ total outcome} [/tex]
[tex]➠P( even number ) = \frac{3}{6}
[/tex]
[tex]➠P( even number ) = \frac{1}{2}
[/tex]
Answer for condition event B
[tex]➠P ( head \: or \: tail ) = \frac{favourable \: outcome }{ total \: outcome} [/tex]
[tex]➠P ( head \: or \: tail) = \frac{2}{2} [/tex]
[tex]➠P ( head \: or \: tail) = 1[/tex]
[tex]➠P( odd\: number ) = \frac{favourable outcome }{ total outcome} [/tex]
[tex]➠P( odd \: number ) = \frac{3}{6} [/tex]
[tex]➠P( odd \: number ) = \frac{1}{2} [/tex]
Know more :-
[tex]➠P( E ) = \frac{favourable outcome }{ total outcome}
[/tex]
[tex]➠P( E ) + P ( not E ) = 1[/tex]