18. The product of two consecutive odd numbers is 10 more than the
square
of the smaller number. Find the sm

2 thoughts on “<br /><br />18. The product of two consecutive odd numbers is 10 more than the<br />square<br />of the smaller number. Find the sm”

1. Solution:

   Let the first odd number be x.

   So, second odd number = x + 2.

   According to the condition,

   → Product of two numbers = 10 + Square of smaller number.

   → x(x + 2) = 10 + x²

   → x² + 2x = 10 + x²

   → 2x = 10

   → x = 5

   ★ So, the smaller number is 5.

   Answer:

   • The smaller number is -5.

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2. Answer:

   5,7

   Step-by-step explanation:

   The numbers will be as follows : x,x+2

   X(x+2)=10+(x²)

   X²+2x=10+x²

   2x=10

   X=10/2

   X=5

   The other number will be x+2 = 7

   Verify:

   5(7)=10+5²

   35=10+25

   35=35

   Hence verified

   The numbers are 5 and 7

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