18. A tree is broken at a height of 12 m from the ground and its top touches theground at the distance of 16 m from the base. Find the original height of the tree. About the author Eloise
Answer: 32m Step-by-step explanation: Let the broken part of the tree, the remaining part and the distance between the broken part and the base of the tree form a right triangle By Pythagoras theorem the broken part=√(distance between the broken part and the base)^2 + (remaining part)^2 √(144+256) =20m the original ht of the tree = Broken part+Remaining part =32m Reply
Answer:
32m
Step-by-step explanation:
Let the broken part of the tree, the remaining part and the distance between the broken part and the base of the tree form a right triangle
By Pythagoras theorem
the broken part=√(distance between the broken part and the base)^2 + (remaining part)^2
√(144+256)
=20m
the original ht of the tree = Broken part+Remaining part
=32m