16. A submarine 9 metres in height is floating on water. If į of its height is
under water, then what is the height of the su

2 thoughts on “16. A submarine 9 metres in height is floating on water. If į of its height is<br />under water, then what is the height of the su”

1. Answer:

   ANSWER:−

   9 \bold{(3)/(4) \: = 9\huge \frac{3}{4} }9(3)/(4)=9

   4

   3

   above hight = total – under

   \implies \bold{ 9 \huge \frac{3}{4} \small \: m – \huge \frac{1}{3} ( \small9 \huge\frac{3}{4}) \small m}⟹9

   4

   3

   m−

   3

   1

   (9

   4

   3

   )m

   \bold{ \implies9 \huge\frac{3}{4} (1 – \frac{1}{3} )m}⟹9

   4

   3

   (1−

   3

   1

   )m

   \implies \huge \bold{ \frac{39}{4} ( \frac{3 – 1}{3})m }⟹

   4

   39

   (

   3

   3−1

   )m

   \implies\huge \bold{ \frac{ \cancel{39} {}^{13} }{ \cancel{4} {}^{2} } \times \frac{ \cancel2}{ \cancel{3}} }⟹

   4

   2

   39

   13

   ×

   3

   2

   \implies \huge \bold{\frac{13}{2} m}⟹

   2

   13

   m

   \huge \red \star \bold{ \: 6 \frac{1}{2} \: m }⋆6

   2

   1

   m

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2. A submarine 39/4 m in height is floating on water is if 1/3 of its height is underwater then what is the height of the submarine visible above water

   Submarine height = 39/4 m

   1/3 of submarine = (1/3) * (39/4) = 13/4 m

   Height visible above water = Submarine height – inside water

   => Height visible above water = 39/4 – 13/4

   => Height visible above water = 26/4

   => Height visible above water = 13/2 m = 6.5 m

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