15. Find the equation of the line that is parallel to 2x + 5y – 7 = 0 and passes through the
mid-point of the line segment joining the points (2,7) and (-4,1).
16. Find the equation of the line that is perpendicular to 3x + 2y – 8 =0 and passes through
the mid-point of the line segment joining the points (5,-2) and (2, 2).
Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0
parallel to the line 3x
7u
Step-by-step explanation:
Given line: 2x+5y−7=0
5y=−2x+7
y=(5−2)x+57
So, the slope is 5−2
Hence, the slope of the line that is parallel to the given line will be the same, m=5−2
Now, the mid – point of the line segment joining point (2,7) and (−4,1) is
(2(2−4),2(7+1))=(−1,4)
Thus, the equation of the line will be
y−y1=m(x−x1)
y−4=(5−2)(x+1)
5y−20=−2x−2
2x+5y=18
Answer:
Step-by-step explanation:
Given line: 2x+5y-7-0
5y=-2x+7
y=(5-2)x+57
So, the slope is 5-2
Hence, the slope of the line that is parallel to the
given line will be the same, m-5-2
Now, the mid-point of the line segment joining
point (2,7) and (-4,1) is
(2(2-4),2(7+1))=(-1,4)
Thus, the equation of the line will be
y-y1-m(x-x1)
y-4-(5-2)(x+1)
5y-20–2x-2
2x+5y=18