12000 is divided into two parts. Sum of 30% of the first part and 50% of the second part gives you 5000. Find the two parts. Please fast:( About the author Emma
Answer: 5000 and 7000 Step-by-step explanation: Let 12000 be divided in to ‘x’ and ‘y’ parts x + y=12000 . . . . .(1) According to question 30/100(x)+50/100(y)=5000 3x/10+5y/10=5000 3x+5y=50000 . . . ..(2) Multiply eqn (1) by 3 3x+3y=36000 . . .. . .(3) (2)-(3) 3x+5y-3x-3y=14000 2y=14000 y=7000 . . . . put in (1) x=5000 So Number should be divided in to 5000 and 7000 Reply
Answer:
5000 and 7000
Step-by-step explanation:
Let 12000 be divided in to ‘x’ and ‘y’ parts
x + y=12000 . . . . .(1)
According to question
30/100(x)+50/100(y)=5000
3x/10+5y/10=5000
3x+5y=50000 . . . ..(2)
Multiply eqn (1) by 3
3x+3y=36000 . . .. . .(3)
(2)-(3)
3x+5y-3x-3y=14000
2y=14000
y=7000 . . . . put in (1)
x=5000
So Number should be divided in to 5000 and 7000