12. Out of 2000 families with 4 children each, the number of families you would expect to have no girls is11 1p =q = 1(A) 300(B) 150(C) 200(D) 125 About the author Liliana
Answer: 1250 Step-by-step explanation: probability of 1 girl = 4c1*(1/2)*(1/2)^3=1/4 probability of 2 girls = 4c2*(1/2)^2 * (1/2)^2= 3/8 So the OR of the above = (1/4)+(3/8)=5/8 So again, expected no. of families with that criteria = 5/8 * 2000 = 1250 I think you give wrong answer in D, Please mark me as brilliant Reply
Answer:
1250
Step-by-step explanation:
probability of 1 girl = 4c1*(1/2)*(1/2)^3=1/4
probability of 2 girls = 4c2*(1/2)^2 * (1/2)^2= 3/8
So the OR of the above = (1/4)+(3/8)=5/8
So again, expected no. of families with that criteria = 5/8 * 2000 = 1250
I think you give wrong answer in D, Please mark me as brilliant
Answer:
may be 150 families wouldn’t have girls