111 cows, 185 sheep and 296 goats are to be taken across a river. There is only one boat and the boatsman says; he will take the same number and same kind of animals in each trip. Find the largest number of animals in each trip. About the author Kylie
Answer: He will take 37 of one kind in each trip Step-by-step explanation: We need to find the HCF to of 111, 185 and 296 By prime factorization, 111 = 3 x 37 185 = 5 x 37 296 = 2³ x 37 So the HCF is 37 So, he will take 37 animals in each trip Hope this helps Pls mark me as brainliest Reply
Answer:
He will take 37 of one kind in each trip
Step-by-step explanation:
We need to find the HCF to of 111, 185 and 296
By prime factorization,
111 = 3 x 37
185 = 5 x 37
296 = 2³ x 37
So the HCF is 37
So, he will take 37 animals in each trip
Hope this helps
Pls mark me as brainliest