11. In POR, PQ – QR and in PSR, PS = SR.(a) Is ASPQ = ASRO?(b) Prove that ZSPO = SRO About the author Madelyn
Step-by-step explanation: Given: in ΔPSR, Q is a point on the side SR such that PQ = PR. In ΔPRQ, PR = PQ (given) ⇒ ∠PRQ = ∠PQR (opposite angles to equal sides are equal) But ∠PQR > ∠PSR (exterior angle of a triangle is greater than each of opposite interior angle) =>∠PRQ > ∠PSR ⇒ PS > PR (opposite sides to greater angle is greater) ⇒ PS > PQ (as PR = PQ) proved Reply
Step-by-step explanation:
Given: in ΔPSR, Q is a point on the side SR such that PQ = PR.
In ΔPRQ,
PR = PQ (given)
⇒ ∠PRQ = ∠PQR (opposite angles to equal sides are equal)
But ∠PQR > ∠PSR (exterior angle of a triangle is greater than each of opposite interior angle) =>∠PRQ > ∠PSR
⇒ PS > PR (opposite sides to greater angle is greater)
⇒ PS > PQ (as PR = PQ)
proved