10. Find the remainder in each of the following cases:(0) When (2×4 – 6×3 + 2×2 – x + 2) is divided byX + 1.(ii) When 13x° -5x(x – 2) – V6(x² + 2) +2/3(x+2) is divided by (x – 2). About the author Peyton
[tex] \bold \red{answer}[/tex] If x + 2 = 0 x = -2 f(x) = 2×4 – 6×3 + 2×2 – x + 2, [By remainder theorem] f(x) = 2(-2)4 – 6(-2)3 + 2(- 2)2 – (- 2) + 2 = 2(16) – 6(- 8) + 2(4) + 2 + 2 = 32 + 48 + 8 + 2 + 2 = 92 Hence, required remainder = 92. Reply
[tex] \bold \red{answer}[/tex]
If x + 2 = 0
x = -2
f(x) = 2×4 – 6×3 + 2×2 – x + 2, [By remainder theorem]
f(x) = 2(-2)4 – 6(-2)3 + 2(- 2)2 – (- 2) + 2
= 2(16) – 6(- 8) + 2(4) + 2 + 2
= 32 + 48 + 8 + 2 + 2 = 92
Hence, required remainder = 92.