10. Find the least number that when divided by 16, 18
20 leaves remainder 4 in each case but is completely
divisible by

10. Find the least number that when divided by 16, 18
20 leaves remainder 4 in each case but is completely
divisible by 7.

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  1. Answer:

    • So, for the value of x = 4, the required number comes 2884. remainder 4 in each case but exactly divisible by 7
    • This is the right answer for your question.
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