Step-by-step explanation: Given sin(A+B)=1 ⇒sin(A+B)=sin90 o (∵sin90 o =1) ⇒A+B=90 o …………(1) Again, cos(A−B)= 3 /2 ⇒cos(A−B)=cos30 o (∵cos30 o = 3 /2) ⇒A−B=30 o …………(2) Adding (1)+(2) A+B+A−B=90 o +30 o ⇒2A=120 o ⇒A=120/2 ⇒A=60 o Putting A=60 o in equation-(2) we get A−B=30 o ⇒60 o −B=30 o ⇒60 o −30 o =B ⇒B=30 o ∴A=60 o ;B=30 o . Reply
Answer:
A cosec B sec
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Step-by-step explanation:
Given sin(A+B)=1
⇒sin(A+B)=sin90
o
(∵sin90
o
=1)
⇒A+B=90
o
…………(1)
Again, cos(A−B)=
3
/2
⇒cos(A−B)=cos30
o
(∵cos30
o
=
3
/2)
⇒A−B=30
o
…………(2)
Adding (1)+(2)
A+B+A−B=90
o
+30
o
⇒2A=120
o
⇒A=120/2
⇒A=60
o
Putting A=60
o
in equation-(2) we get
A−B=30
o
⇒60
o
−B=30
o
⇒60
o
−30
o
=B
⇒B=30
o
∴A=60
o
;B=30
o
.