1)Find the sum of first 1000 positive integers.please give some step by step answer it means a lot to me About the author Bella
Answer: 500500 Step-by-step explanation: To find out the answer, we must apply the formula, [tex]\frac{n(n+1)}2[/tex] Over here, n = the number of integers, which in this case is 1000. Now lets apply the formula and solve the question: [tex]\frac{n(n+1)}2[/tex] = [tex]\frac{1000(1000+1)}2[/tex] = [tex]\frac{1000(10001)}2[/tex] = [tex]{500*1001}[/tex] – I have cancelled 2 and 1000 = 500500 Thus, the sum of the 1st 1000 positive integers are 500500 _________________________ Hope it helps Please mark as brainliest 🙂 Reply
formula n(n+1)/2 just substitute n= 1000 1000(1000+1)/2 1000*1001/2 500*1001 500500 final answer Reply
Answer:
500500
Step-by-step explanation:
To find out the answer, we must apply the formula, [tex]\frac{n(n+1)}2[/tex]
Over here, n = the number of integers, which in this case is 1000.
Now lets apply the formula and solve the question:
[tex]\frac{n(n+1)}2[/tex] = [tex]\frac{1000(1000+1)}2[/tex]
= [tex]\frac{1000(10001)}2[/tex]
= [tex]{500*1001}[/tex] – I have cancelled 2 and 1000
= 500500
Thus, the sum of the 1st 1000 positive integers are 500500
_________________________
Hope it helps
Please mark as brainliest 🙂
formula n(n+1)/2
just substitute n= 1000
1000(1000+1)/2
1000*1001/2
500*1001
500500 final answer