1. Find the area of a quadrilateral one of whosediagonals is 30 cm long and the perpendicularsfrom the other two vertices are 19 cm and11 cm respectively. About the author Luna
Step-by-step explanation: [tex]area \: of \: quadrilateral \: = \frac{1}{2} \times (h1 + h2) \times diagonal \\ = \frac{1}{2} \times (19 + 11) \times 30 \\ = \frac{1}{2} \times 30 \times 30 \\ = 450 {cm}^{2} [/tex] Pls Mark this answer as the brainliest Reply
Step-by-step explanation:
[tex]area \: of \: quadrilateral \: = \frac{1}{2} \times (h1 + h2) \times diagonal \\ = \frac{1}{2} \times (19 + 11) \times 30 \\ = \frac{1}{2} \times 30 \times 30 \\ = 450 {cm}^{2} [/tex]
Pls Mark this answer as the brainliest