1. Decide whether the values given against each other are the solutions of that equation or not : (1) 5x + 4/2x + 1 = 2, x = 2, -2

1. Decide whether the values given against each other are the solutions of that equation or not : (1) 5x + 4/2x + 1 = 2, x = 2, -2, 0​
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Audrey

1 thought on “1. Decide whether the values given against each other are the solutions of that equation or not : (1) 5x + 4/2x + 1 = 2, x = 2, -2”

  1. Step-by-step explanation:

    p(x)=5x+4/2x+1=2

    p(2)=5(2)+4/2(2)+1=2

    =10+1+1=2

    12-2=10

    p(-2)=5(-2)+4/2(-2)+1=2

    -10+1+1=2

    -8=2

    -6

    p(0)=5(0)+4/2(0)+2=2

    =0+0+2=2

    2=2

    2-2=0

    there fore 0 is equal to 2

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