1. AABC is isosceles in which AE IBC, AE = 6 cm , BC = 9 cm, the area ofAABC is(b) 54 cm(c) 22.5 cm?(d) 45(a) 27 cm?cm? About the author Peyton
Answer: a 27 cm Step-by-step explanation: ae is base is 6cm and heights bc is 9 CM so area of triangle= 1/2 ×base ×height = 1/2×6×9=27cm Reply
Answer:
a 27 cm
Step-by-step explanation:
ae is base is 6cm
and heights bc is 9 CM
so area of triangle= 1/2 ×base ×height
= 1/2×6×9=27cm