1. AABC is isosceles in which AE IBC, AE = 6 cm , BC = 9 cm, the area of
AABC is
(b) 54 cm
(c) 22.5 cm?
(d) 45

1. AABC is isosceles in which AE IBC, AE = 6 cm , BC = 9 cm, the area of
AABC is
(b) 54 cm
(c) 22.5 cm?
(d) 45
(a) 27 cm?
cm?​

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1 thought on “1. AABC is isosceles in which AE IBC, AE = 6 cm , BC = 9 cm, the area of<br />AABC is<br />(b) 54 cm<br />(c) 22.5 cm?<br />(d) 45”

  1. Answer:

    a 27 cm

    Step-by-step explanation:

    ae is base is 6cm

    and heights bc is 9 CM

    so area of triangle= 1/2 ×base ×height

    = 1/2×6×9=27cm

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