1) A picture is 7 3/5 cm wide. How much should it be trimmed to fit in a frame 7 3/10 cm wide?

2) What should be added

1 thought on “1) A picture is 7 3/5 cm wide. How much should it be trimmed to fit in a frame 7 3/10 cm wide? <br /><br />2) What should be added”

1. Answer:

   1. 3/10
   2. 10+(2/5)
   3. 1+(2/15)
   4. 2/3. By 1/9

   Step-by-step explanation:

   1)

   [tex]7 \frac{3}{5} – 7 \frac{3}{10} = \frac{7 \times 5 + 3}{5} – \frac{7 \times 10 + 3}{10} = \frac{38}{5} – \frac{73}{10} = \frac{38 \times 2}{5 \times 2} – \frac{73}{10} = \frac{76}{10} – \frac{73}{10} = \frac{3}{10}[/tex]

   2)

   [tex]18 – 7 \frac{3}{5} = 18 – \frac{38}{5} = \frac{18}{1} – \frac{38}{5} = \frac{90}{5} – \frac{38}{5} = \frac{90 – 38}{5} = \frac{52}{5} = 10 \frac{2}{5} [/tex]

   3)

   [tex]8 \frac{2}{5} – 7 \frac{4}{15} = \frac{8 \times 5 + 2}{5} – \frac{7 \times 15 + 4}{15} = \frac{42}{5} – \frac{109}{15} = \frac{42 \times 3}{5 \times 3} – \frac{109}{15} = \frac{126}{15} – \frac{109}{15} = \frac{126 – 109}{15} = \frac{17}{15} = 1\frac{2}{15} [/tex]

   4)

   [tex] \frac{2}{3} = \frac{2 \times 3}{3 \times 3} = \frac{6}{9} \\ \frac{6}{9} – \frac{5}{9} = \frac{1}{9} [/tex]

   Here 2/3 is greater than 5/9 because 6/9 is the form of 2/3 but with denominator 9.

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